Write down the reaction equation: P → P2O5 → H3PO4 → Na3PO4

1. Combustion of phosphorus in excess dry air:

P4 + 5O2 = P4O10 (P2O5).

2. Phosphorus oxide dissolves in water to form tetra-metaphosphoric acid:

P4O10 + 2H2O = (HPO3) 4.

When boiled, acid decomposes:

(HPO3) 4 + 4H2O = 4H3PO4.

3. Reaction of phosphoric acid with an excess of alkali:

Н3РО4 + 3NaOH = Na3PO4 + 3H2O.

The reaction proceeds in stages:

NaH2PO4 => Na2HPO4 => Na3PO4.



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