Write down the reaction equations: Butane, 2-chlorobutane; butene-2; butanol-2.

Let’s write down the equations for organic substances:
1. Н3С – СН2 – СН2 – СН3 + Cl2 = H3C – CHCl – CH2 – CH3 + HCl – substitutions, 2-chloro butane was obtained;
2. Н3С – СНCl – CH2 – CH3 + KOH = H3C – CHOH – CH2 – CH3 + KCl – exchange, butanol – 2 is released;
3. Н3С – СНОН – СН2 – СН3 = Н2О + Н3С – СН = СН – СН3 – dehydration, butene-2 is released;
4. Н3С – СН = СН – СН3 + Н2О = Н3С – СН – ОН – СН2 – СН3 – hydration, butanol – 2 was obtained.
The processes show the relationship between hydrocarbons and oxygen-containing organic substances by the example of butane, butanol.