Write down the reaction equations for the following transformations: Al ⇾ Al (OH) 3 Al2O3 ⇾ AlСl3 ⇾Al (OH) 3

| November 17, 2020 | education

Write down the reaction equations for the following transformations: Al ⇾ Al (OH) 3 Al2O3 ⇾ AlСl3 ⇾Al (OH) 3 Consider the first one as OVP, and write the last in ionic form.

We write down the reaction equation for the next chain of reactions. Al ⇾ Al (OH) 3 Al2O3 ⇾ AlСl3 ⇾Al (OH) 3 1) Al + 3H2O = Al (OH) 3 + Н2 Al ° -> Al + 3 (- 3) oxidation, reducing agent 2Н + 1 -> Н2 ° (+ 1 reduction, oxidizer 2) 2Al (OH) 3 + 3CO2 = Al2O3 + 3Ca (OH) 2 When aluminum hydroxide and carbon monoxide interact, aluminum oxide and calcium hydroxide are formed. Al2O3 + 6HCl = 2 AlCl3 + 3H2O When aluminum oxide and hydrochloric acid react, aluminum chloride and water are formed. 2 AlCl3 + 6H2O = 2Al (OH) 3 + 3Cl2 When aluminum oxide and water interact, aluminum hydroxide and chlorine are formed. We write it in ionic form. 2Al (3+) + 6Cl (-) + 6H2O = 2Al (OH) 3 + 6Cl (-) 2Al (3+) + 6H2O = 2Al (OH)



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