Write down the reaction equations for the interaction of sulfuric acid with copper oxide and barium chloride

Write down the reaction equations for the interaction of sulfuric acid with copper oxide and barium chloride in both male and ionic forms.

1) The reaction takes place between substances such as sulfuric acid and copper oxide. As a result of the reaction, a substance is formed: copper sulfate salt and water is released. The molecular equation of the reaction can be written as follows:

H2SO4 + CuO = CuSO4 + H2O
The ionic reaction equation can be written as follows:

2 H + + SO4 – + CuO = Cu 2+ + SO4 – + H + + OH
The abbreviated ionic equation can be written as follows:

2 H + + CuO = Cu2 + + H + + OH –

2) The reaction takes place between sulfuric acid and barium chloride salt. Formed as a result of the reaction, a salt of barium sulfate and hydrochloric acid is formed. Graphically, this equation of a chemical reaction can be expressed as follows:

H2SO4 + BaCl2 = BaSO4 + 2 HCl.
The ionic reaction equation can be written as follows:

2 H + + SO4- + Ba 2+ + 2 Cl – = BaSO4 + 2 H + + 2 Cl-
The abbreviated ionic equation can be written as follows:

SO4 – + Ba2 + = BaSO4.