Write down the reaction equations with which you can carry out the following transformations

Write down the reaction equations with which you can carry out the following transformations: a) Cu-Cao-Ca (OH) 2-CaCl2-Ca3 (PO4) 2 B) phosphorus-phosphorus oxide (5), phosphoric acid, potassium phosphate-calcium phosphate Equations with the participation of electrolytes, write down in molecular and ionic form. For redox reactions, draw up electronic balance diagrams.

1. Make the equation for the reaction of calcium combustion. As a result, calcium oxide is formed.

2Ca + O2 = 2CaO.

2Ca0 + O2 0 = 2Ca + 2 O-2

Ca0 – 2e Ca +2 reducing agent, gives off 2 e, is oxidized.

O20 + 2e O-2 oxidizer, takes 2 e, is restored.

2. Calcium oxide – basic oxide, reacting with water, forms a base – calcium hydroxide.

CaO + H2O = Ca (OH) 2.

3. The reaction between calcium hydroxide and hydrochloric acid proceeds with the formation of calcium chloride and water.

Ca (OH) 2 + 2HCl = CaCl2 + 2H2O.

Ca + 2 + 2OH-1 + 2H + 1 + 2Cl-1 = Ca + 2 + 2Cl-1 + 2H2O.

2H + 1 + 2OH-1 = 2H2O.

3CaCl2 + 2H3PO4 = Ca3 (PO4) 2 + 6HCl.

3Ca + 2 + 6Cl-1 + 6H + 1 + PO4-3 = Ca3 (PO4) 2 + 6H + 1 + 6Cl-1.

3Ca + 2 + PO4-3 = Ca3 (PO4) 2.

B) P – P2 O5 – H3PO4 – K3 P O4 – Ca3 (PO4) 2.

P0 + O2 0 = P2 + 5O5-2

Р0 -5е Р +5 reducing agent, is oxidized.

O2 0 + 2 e O-2 oxidizing agent, reduced.

P2 O5 + 3H2O = 2H3PO4

Н3РО4 + 3KOH = К3Р О4 + 3H2O.

3H + 1 + PO4 -3 + 3K + 1 + 3OH-1 = 3K + 1 + P O4-3 + 3H2O.

3H + 1 + 3OH-1 = 3H2O.

2K3P O4 + 3CaCl2 = Ca3 (PO4) 2 + 6KCl.

6K + 1 + P O4 -3+ 3Ca + 2 + 2Cl-1 = Ca3 (PO4) 2 + 6K + 1 + 6Cl-1.

3Ca + 2 + P O4 -3 = Ca3 (PO4) 2.