Write down the thermochemical equation of the combustion of acetylene, if heat was released during

Write down the thermochemical equation of the combustion of acetylene, if heat was released during the combustion of 260 grams, in the amount of 52,200 kJ, if the equation of combustion of acetylene: 2С2Н2 + 5О2 = 4СО2 + 2Н2О + Q

Let’s find the amount of acetylene substance:

n (C2H2) = m (C2H2) / M (C2H2) = 260/26 = 10 mol;

The amount of heat released is directly proportional to the amount of acetylene burned out. Using the proportional method, we find how much heat will be released during the combustion of 2 mol C2H2.

5 mol – 52,200 kJ;

2 mol – Q kJ;

Multiplying crosswise, we get:

5 * Q = 2 * 52200;

Q = 20880 kJ.

2С2Н2 + 5О2 = 4СО2 + 2Н2О + 20880 kJ