Write down two equations for the reactions of oxygen with simple and complex substances.
Write down two equations for the reactions of oxygen with simple and complex substances. Determine the oxidation states and indicate the oxidizing agent and reducing agent.
1 N2 (0) + O2 (0) = 2N (+2) O (-2) – nitric oxide (I)
O2 + 2e = 2O (-2) | LCM: 2 | 1
N2 – 2e = 2N (+2) | | 1
LCM is the least common multiple. It is not necessary to write the NOC, but there should be 2 in the middle.
2 S (0) + O2 (0) = S (+4) O (-2) – sulfur (IV) oxide
O2 + 2e = 2O (-2) INOK: 4I 2
S – 4e = S (+4) I I 1
3 4H (+) Cl (-) + O2 (0) = Cl2 (0) + 2H (+) 2O (-2)
salt to-that
O2 + 2e = 2O (-2) | LCM: 2I 1
Cl2 (-) – 2e = 2Cl (0) | I 1
4.2Cu2 (+) S (-2) + 3O2 (0) = 2Cu (+) O (-2) + 2S (+4) O (-2)
copper sulfate (I) copper (II) sulfur (IV)
O2 (-2) + 2e = 2O (-2) INOK: 6I 3
S (-2) – 6e = S (+4) I I 1