Write equations to 1) sodium oxide + water → sodium hydroxide 2) iron oxide (2) + aluminum → t aluminum oxide + iron 3) copper hydroxide (2) → t copper oxide (2) + water
1. Formation of sodium hydroxide.
NaO + H2O = NaOH.
2. Reaction of substitution of iron for aluminum.
3FeO + 2Al = Al2O3 + 3Fe.
3. Decomposition of powdered copper hydroxide occurs at 200 ° C, and in the form of a suspension at low temperatures – 40-80 ° C.
Cu (OH) 2 = CuO + H2O.
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