Write full and abbreviated ionic equations of reactions between solutions of substances: CuSO4 and KOH.

Write full and abbreviated ionic equations of reactions between solutions of substances: CuSO4 and KOH. FeCl3 and NaOH. RbOH and HC1. K2CO3 and H2SO4.

А).

The products of the reaction between copper sulfate and potassium hydroxide are potassium sulfate and copper hydroxide, which precipitates.

CuSO₄  + 2KOH = K₂SO₄ + Cu(OH)₂↓.

Cu²⁺  + SO₄^2-  + 2K¹⁺ 2 OH^1- = 2K ¹⁺SO₄^2- + Cu(OH)₂↓.

Cu²⁺  +2 OH^1- =  Cu(OH)₂↓.

B).

The products of the reaction between iron (III) chloride and sodium hydroxide are sodium chloride and iron (III) hydroxide, which precipitates.

FeCl₃ +  3NaOH = 3NaCl + Fe(OH)₃↓.

Fe³⁺ + 3 Cl^1- +  3Na¹⁺+ 3 OH^1- = 3Na¹⁺ + 3 Cl^1- + Fe(OH)₃↓.

Fe³⁺ + 3 OH^1- =  Fe(OH)₃↓.

С). The products of the reaction between rubidium hydroxide and hydrochloric acid are rubidium chloride and water.

RbOH + HCl = RbCl  + H₂O.

Rb¹⁺ + OH^1- + H¹⁺ + Cl^1-= Rb¹⁺ + OH^1- + H₂O.

H¹⁺  + OH^1-  =  H₂O.

D). The products of the reaction between potassium carbonate and sulfuric acid are potassium sulfate, water and carbon dioxide.

K₂CO₃ + H₂SO₄ = K₂SO₄ + CO₂ ↑+ H₂O.

2K ¹⁺+ CO₃^2- + 2H¹⁺ + SO₄ ^2-= 2K¹⁺ + SO₄^2- + CO₂ ↑+ H₂O.

2H¹⁺ + CO₃^2- =  CO₂ ↑+ H₂O.