Write the equation for the reaction of alcoholic fermentation of glucose, knowing that as a result

Write the equation for the reaction of alcoholic fermentation of glucose, knowing that as a result of it, ethyl alcohol and carbon dioxide are formed. Calculate how many grams of a 40% solution of ethyl alcohol can be obtained from 5 mol of glucose.

1. Let’s write the equation of the ongoing fermentation:

C6H12O6 → 2C2H5OH + 2CO2 ↑.

2. The amount of alcohol produced is twice the amount of glucose:

n (C2H5OH) = n (C6H12O6) * 2 = 5 * 2 = 10 mol.

3. Calculate the mass of ethanol:

m (C2H5OH) = n (C2H5OH) * M (C2H5OH);

M (C2H5OH) = 2 * 12 + 5 + 17 = 46 g / mol;

m (C2H5OH) = 10 * 46 = 460 g.

4. Determine the mass of the alcohol solution:

m (solution) = m (C2H5OH): w (C2H5OH) = 460: 0.4 = 1150 g.

Answer: 1150