Write the equation for the reaction of phosphorus combustion. Calculate how much oxygen

Write the equation for the reaction of phosphorus combustion. Calculate how much oxygen is required to completely burn 62g of phosphorus.

Let’s execute the solution step by step:
1. Let’s compose the reaction equation:
4P + 5O2 = 2P2O5 – the reaction of phosphorus combustion occurs with the participation of oxygen, phosphorus oxide is released (5);
3. Let’s make calculations using the formulas:
M (P) = 30.97 g / mol;
Y (P) = m (P) / M (P) = 62 / 30.97 = 2 mol;
4. Let’s make a proportion according to the reaction equation:
2 mol (P) – X mol (O2);
-4 mol -5 mol hence, X mol (O2) = 2 * 5/4 = 2.5 mol;
5. Let’s calculate the volume of О2 according to Avogadro’s law:
V (O2) = 2.5 * 22.4 = 56 liters.
Answer: The combustion reaction requires 56 liters of oxygen.