Write the equation of the circle tangent to the coordinate axes at points (-3; 0) and (0; -3).

Let us represent these points (- 3; 0) and (0; – 3) in the coordinate system. From these points, draw straight lines to the intersection at point A (- 3; – 3) – this is the center of the circle.

It can be seen that the radius of this circle is 3.

General view of the circle equation: (x – a) ^ 2 + (y – b) ^ 2 = r ^ 2, where a and b are the coordinates of the center of the circle, r is the radius. substitute for a = – 3; b = – 3; r = 3.

(x – (- 3)) ^ 2 + (y – (- 3)) ^ 2 = 32;

(x + 3) ^ 2 + (y + 3) ^ 2 = 9.