Write the equation of the combustion reactions, hydrogenation, chlorination and hydration for butene 2.

Let’s implement the solution:
1. Let’s compose the structural formula of butene – 2:
H3C – CH2 – CH = CH2
2. Due to the double bond in the unsaturated hydrocarbon molecule, hydrogenation, chlorination, hydration are possible, and the combustion reaction also takes place.
С4Н8 + 6О2 = 4СО2 + 4Н2О – combustion, carbon dioxide and water are released;
Н3С – СН2 – СН = СН2 + Н2 = Н3С – СН2 – СН2 – СН3 – hydrogenation, butane was obtained;
Н3С – СН2 – СН = СН2 + Сl2 = H3C – CH2 – CHCl – CH2Cl – chlorination, dichlorobutane was formed;
Н3С – СН2 – СН = СН2 + Н2О = Н3С – СН2 – СНОН – СН3 – hydration, butanol – 2 is released.