Write the equation of the straight line passing through the point M (-1; 4) parallel to the straight line y = 12-3x.

To begin with, we write the equation of the straight line in general form:

y = kx + b.

In the initial data for this task, it is reported that the desired straight line must be parallel to the straight line y = 12 – 3x.

The straight line y = kx + b will be parallel to the straight line y = 12 – 3x, if the slopes of these straight lines are equal, that is, the condition must be met:

k = -3.

Also in the condition of the problem it is said that the desired straight line must pass through the point M (-1; 4).

Substituting the value x = -1, y = 4 into the equation of the straight line y = -3x + b, we get:

4 = -3 * (-1) + b;

4 = 3 + b;

b = 4 – 3 = 1.

Thus, the desired equation of the straight line y = -3x + 1.

Answer: y = -3x + 1.