Write the equation of the tangent to the graph of the functions y = sinx + 1 at the point (n / 2; 0).

We have the function f (x) = sin x + 1.

Let us write the equation of the tangent to the graph of the function at a point with an abscissa at the point x0 = П / 2.

The equation of the tangent to the graph is as follows:

y = f ‘(x0) * (x – x0) + f (x0);

Let’s find the derivative of the function and its value from the argument x0:

f ‘(x) = cos x;

f ‘(x0) = cos P / 2 = 0;

Find the value of the function from the argument x0:

f (x0) = sin (P / 2) + 1 = 1 + 1 = 2.

Accordingly, the tangent equation will be:

y = 2.