Write the equations Cu – CuO – Cu (OH) 2 – CuSO4 S – SO3 – H2SO4

A) 1) Copper interacts with oxygen, forms – copper (II) oxide:

2Cu + O2 → 2CuO;

2) Copper oxide must react with water, but due to the fact that such a reaction is not possible, the transformation is carried out in two stages:

a) the interaction of copper oxide with hydrochloric acid:

CuO + HCl → CuCl2 + H2O;

b) interaction of copper chloride with potassium hydroxide:

CuCl2 + 2KOH → 2KCl + Cu (OH) 2;

3) When copper hydroxide interacts with sulfuric acid, it turns out – copper sulfate and water:

Cu (OH) 2 + H2SO4 → CuSO4 + 2H2O.

B) 1) Sulfur reacts with oxygen and sulfur oxide (IV) is formed:

S + O2 → SO2;

When sulfur (IV) oxide interacts with oxygen, we obtain sulfur oxide (VI):

2SO2 + O2 → 2SO3;

2) Sulfur oxide (VI) reacts with water and it turns out – sulfuric acid:

SO3 + H2O → H2SO4.