Write the law of harmonic oscillation of a load on a spring if the amplitude of oscillation is 80 cm

Write the law of harmonic oscillation of a load on a spring if the amplitude of oscillation is 80 cm and the period of oscillation is 0.5 sec.

If the pendulum was told to move without initial velocity (released), the law of harmonic oscillations has the form (cosine law):

x = A * cos (ωt + φ).

If the pendulum was told to move by means of a blow, the law of harmonic oscillations has the form (sine law)

x = A * sin (ωt + φ).

Given: A is the amplitude (A = 80 cm = 0.8 m), T is the oscillation period (T = 2 s, we express the cyclic frequency through the period; ω = 2Π / T = Π), the initial phase is not indicated, we consider it equal zero.

x = 0.8 * cos Πt.

x = 0.8 * sin Πt.