Write the molecular and ionic equations for the reactions of nitric acid with copper (II) hydroxide, iron (III) oxide, and sodium carbonate.

univerkov | November 29, 2020 | education

1.molecular: 2HNO3 + Cu (OH) 2 = Cu (NO3) 2 + 2H2O
full ionic: 2H (1+) + 2NO3 (1-) + Cu (OH) 2 = Cu (2+) + 2NO3 (1-) + 2H2O
abbreviated ionic: 2H (1+) + Cu (OH) 2 = Cu (2+) + 2H2O
2.molecular: 6HNO3 + Fe2O3 = 2Fe (NO3) 3 + 3H2O
full ionic: 6H (1+) + 6NO3 (1-) + Fe2O3 = 2Fe (3+) + 2 (NO3) 3 (1-) + 3H2O
reduced ionic: 6H (1+) + Fe2O3 = 2Fe (3+) + 3H2O
3.molecular: 2HNO3 + Na2CO3 = 2NaNO3 + H2O + CO2
full ionic: 2H (1+) + 2NO3 (1-) + 2Na (1+) + CO3 (2-) = 2Na (1+) + 2NO3 (1-) + H2O + CO2
abbreviated ionic: 2H (1+) + CO3 (2-) = H2O + CO2

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