Write the molecular and ionic reaction equations for the following transformation scheme: S03 → H2S04 → Na2S04 → BaS04

S03 (1 reaction) → H2S04 (2 reaction) → Na2S04 (3 reaction) → BaS04

1 reaction:
SO3 + … = H2SO4
Add water to make sulfuric acid. We get:
SO3 + H2O = H2SO4
abbreviated ionic equation SO3 + H2O = 2H (1+) + SO4 (2-)

2 reaction:
H2SO4 + … = Na2SO4
To obtain sodium sulfate, add sodium hydroxide to sulfuric acid. We get:
H2SO4 + 2NaOH = Na2SO4 + 2H2O
abbreviated ionic equation H (1+) + OH (1-) = H2O

3 reaction:
Na2SO4 + … = BaSO4
To obtain barium sulfate, add barium hydroxide to sodium sulfate. We get:
Na2SO4 + Ba (OH) 2 = BaSO4 + 2NaOH
abbreviated ionic equation Ba (2+) + SO4 (2 -) = BaSO4