Write the molecular, complete and abbreviated ionic equation of the reaction between calcium chloride and phosphoric acid.

3CaCl2 + 2H3PO4-> Ca3 (PO4) 2 / precipitate / + 6HCl ~ now you can decompose all substances into ions, except precipitate ~ 3Ca (2 +) + 6Cl (-) + 6H (+) + 2PO4 (3 -) = Ca3 (PO4) 2 / precipitate / + 6H (+) + 6Cl (-) ~ reduce the total ions in the left and right sides ~ 3Ca (2 +) + 2PO4 (3 -) = Ca3 (PO4) 2 / precipitate /



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