Write the molecular formula of sulfur oxide in which the mass ratios of sulfur and oxygen are 1: 1, respectively.

N (S in SxOy) = (ω (S in SxOy) * Mr (SxOy)) / (Ar (S) * 100%) = (50% * Mr (SxOy)) / (32 * 100%) = (Mr (SxOy) / 64);
N (O in SxOy) = (ω (O in SxOy) * Mr (SxOy)) / (Ar (O) * 100%) = (50% * Mr (SxOy)) / (16 * 100%) = (Mr (SxOy) / 32);
N (S in SxOy) / N (O in SxOy) = ((Mr (SxOy) / 64)) / ((Mr (SxOy) / 32)) = 1/2.
Answer: SO2.



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