Write the reaction equation: С – СН4 – С2Н2 -СН3СОН – С2Н5ОН – С2Н5ОNa

Let’s write the equations:
С + 2Н2 + СН4 – the reaction of the compound, methane is formed;
2CH4 = C2H2 + 3H2 – decomposition of methane (cracking), acetylene obtained;
C2H2 + H2O = H2C = CH – OH (vinyl alcohol) = H3C – CHO – hydration, an intermediate product of vinyl alcohol is released, which undergoes isomerization and acetaldehyde is released;
Н3С – СНО + Н2 = С2Н5 – ОН – ethyl alcohol is formed;
2С2Н5 – ОН + 2Na = 2C2H5 – ONa + H2 – substitutions, sodium ethylate was obtained.
These reactions confirm the connection between inorganic and organic compounds.