Write the reaction equation: Cu (NO3) 2 → Cu (OH) 2 → CuSO4

Let’s write the reactions in molecular and abbreviated ionic forms:

1.Cu (NO3) 2 → Cu (OH) 2 – exchange reaction between alkali and salt:
Cu (NO3) 2 + 2NaOH = Cu (OH) 2 + 2NaNO3 (formation of a weak electrolyte – insoluble base)
Cu (2+) + 2OH (-) = Cu (OH) 2 – abbreviated ionic equation
2. Cu (OH) 2 → CuSO4 – neutralization reaction between base and acid:
Cu (OH) 2 + H2SO4 = CuSO4 + 2H2O (formation of a weak electrolyte – water)
Cu (OH) 2 + 2H (+) = Cu (2+) + 2H2O – abbreviated ionic equation



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