Write the reaction equation: CuO → CuSO4 → BaSO ↓ CuCl2 → Cu (OH) 2 → CuO

1) Copper oxide reacts with sulfuric acid, during which we observe the formation of copper sulfate and water:

CuO + H2SO4 → CuSO4 + H2O;

2) When copper sulfate and barium hydroxide react, precipitates of barium sulfate and copper hydroxide are formed:

CuSO4 + Ba (OH) 2 → BaSO4 ↓ + Cu (OH) 2 ↓;

3) To obtain copper chloride from copper oxide, it is necessary to add hydrochloric acid to the oxide:

CuO + 2HCl → CuCl2 + H2O;

4) As a result of the exchange reaction of copper chloride and sodium hydroxide, we get – sodium chloride and copper hydroxide:

CuCl2 + 2NaOH → 2NaCl + Cu (OH) 2 ↓;

5) When heated, copper hydroxide decomposes into copper oxide and water:

Cu (OH) 2 ↓ → CuO + H2O.