We write equations for the following chain of reactions:
Na —> NaOH —> NaAlO2 —-> AlCl3 —-> Al (OH) 3
From sodium we get sodium hydroxide, for this we add water to sodium, we get the following reaction:
Na + H2O = NaOH + H2
further from Na OH we get NaAlO2 by adding trivalent aluminum oxide.
2NaOH + Al2O3 = 2NaAlO2 + H2O
then add hydrochloric acid to NaAlO2, resulting in sodium chloride, aluminum chloride and water:
NaAlO2 + 4HCl = NaCl + AlCl3 + 2H2O
Next, add sodium hydroxide to aluminum chloride and get the result of aluminum hydroxide and sodium chloride
AlCl3 + 3NaOH = Al (OH) 3 + 3NaCl
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