Write the reaction equation: propene → 2-bromopropane → propanol-2 → isopropyl formate

We write down the reaction equation for the next chain of reactions.

Propene → 2-bromopropane → propanol-2 → isopropyl formate

1. Getting 2 – bromopropane.

CH2 = CH – CH3 + HBr = CH3 – CH2Br – CH3.

When propene interacts with hydrogen bromide, 2-bromopropane is formed as a result.

2. Getting propanol – 2.

CH3 – CH2Br – CH3 + KOH = CH3 – CH2OH – CH3 + KBr

When bromopropane interacts with potassium hydroxide, propanol-2 and potassium bromine are formed as a result.

3. Obtaining isopropyl formate.

НСООН + СН3 – СНОН – СН3 = НСООСН (СН3) 2 + Н2О

The result is methyl formate.