Write the reaction equation: S-So2-so3-h2so4-so2-na2so3-nano3-O2-P2O5

S → SO2 → SO3 → H2SO4 → SO2 → Na2SO3 → NaNO3 → O2 → P2O5

1) S + O2 = SO2

Let’s arrange the oxidation states of the elements:

S ^ (0) + O ^ (0) 2 = S ^ (+ 4) O ^ (- 2) 2

Let’s draw up an electronic balance diagram, define an oxidizing agent and a reducing agent:

S ^ (0) – 4e → S ^ (+ 4) reducing agent;

2 O ^ (0) + 4e → 2 O ^ (- 2) oxidizing agent;

2) 2 SO2 + O2 = 2 SO3

3) SO3 + H2O = H2SO4

4) 2 H2SO4 + Cu = CuSO4 + SO2 + 2 H2O

5) SO2 + 2 NaOH = Na2SO3 + H2O

We write down the complete ionic equation of the reaction:

SO2 +2 Na ^ (+) + 2 OH ^ (-) = 2 Na ^ (+) + SO3 ^ (2-) + H2O

Let’s compose an abbreviated ionic equation:

SO2 +2 OH ^ (-) = SO3 ^ (2-) + H2O

6) Na2SO3 + 2 HNO3 = 2 NaNO3 + SO2 + H2O

7) 2 NaNO3 = 2 NaNO2 + O2

8) 5 O2 + 4 P = 2 P2O5