Write the reaction equations: 1) Na – NaOH- NaCl- AgCl 2) C- CO- CO2- Na2CO3- CO3

Write the reaction equations: 1) Na – NaOH- NaCl- AgCl 2) C- CO- CO2- Na2CO3- CO3 3) CH4- C- CO2- Na2CO3- CO2 4) Fe- FeCl3- Fe (OH) 2- Fe2O3- Fe

Na → NaOH → NaCl → AgCl

1) During the interaction of metallic sodium with water, we observe the formation of a sodium hydroxide solution and the release of gas bubbles – hydrogen:

2Na + 2H2O → 2NaOH + H2 ↑;
2) Sodium hydroxide reacted with hydrochloric acid, we get sodium chloride and water:

NaOH + HCl → NaCl + H2O;
3) Sodium chloride interacts with silver nitrate – a precipitate of silver chloride and sodium nitrate:

NaCl + AgNO3 → AgCl ↓ + NaNO3.

C → CO → CO2 → Na2CO3 → CaCO3

1) Carbon reacts with oxygen and results in carbon (II) oxide:

2C + O2 → 2CO;

2) Carbon (II) oxide, similarly to the previous reaction, reacts with oxygen and carbon (IV) oxide is obtained:

2CO + O2 → 2CO2;

3) Sodium oxide, when interacting with water, forms sodium carbonate:

Na2O + CO2 → Na2CO3

4) To obtain calcium carbonate from sodium carbonate, it is necessary to add calcium chloride:

Na2CO3 + CaCl2 → CaCO3 + 2NaCl

CH4 → C → CO2 → Na2CO3 → CO2

1) To get carbon from methane, you need to heat it:

CH4 → C + H2 ↑;

2) When carbon is oxidized, we get carbon oxide (IV):

C + O2 → CO2 ↑;

3) Carbon oxide (IV) reacts with sodium hydroxide, and we get sodium carbonate and water:

CO2 + 2NaOH → Na2CO3 + H2O;

4) Sodium carbonate reacts with hydrochloric acid, we get – sodium chloride, water and carbonic oxide (IV):

Na2CO3 + 2HCl → 2NaCl + H2O + CO2.

Fe → FeCl2 → Fe (OH) 2 → Fe (OH) 3 → Fe2O3

1) Iron reacts with chlorine, we get iron (II) chloride:

Fe + 3Cl2 → FeCl2;

2) Iron (II) chloride reacts with sodium hydroxide, a precipitate of iron (II) hydroxide and sodium chloride is obtained:

FeCl2 + NaOH → Fe (OH) 2 ↓ + 2NaCl;

3) The precipitate of iron (II) hydroxide reacts with oxygen and water, we get – ferum (III) hydroxide:

4Fe (OH) 2 + O2 + 2H2O → 4Fe (OH) 3 ↓;

4) Ferum (III) hydroxide decomposes into ferum (III) oxide and water, when exposed to temperature:

2Fe (OH) 3 → Fe2O3 + 3H2O.