Write the reaction equations: a) c6h12o6- c2h5oh- butadiene-1,3- 1,4-dichlorobutene
Write the reaction equations: a) c6h12o6- c2h5oh- butadiene-1,3- 1,4-dichlorobutene b) c6h6- isopropylbenzene- phenol- picric acid
Let us write down the reaction equations for organic substances:
a) С6Н12О6 = 2С2Н5ОН + 2СО2 – glucose fermentation reaction, ethanol was obtained;
С2Н5ОН + НCl = C2H5Cl + H2O – exchange, chloroethane is released;
2C2H5Cl + 2Na = C4H10 – Wurtz reaction, butane formed;
C4H10 = 2H2 + H2C = CH – CH = CH2 – dehydrogenation, 1,3-butadiene was obtained;
H2C = CH – CH = CH2 + Cl2 = H2C – Cl – CH = CH – CH2Cl – addition, 1,4 – dichlorobutene was isolated;
b) С6Н6 + СН3 – СНBr – CH3 = C6H5 – CH – (CH3) 2 – addition reaction;
С6Н5 – СН (-СН3) 2 + О2 = С6Н5 – ОН + СН3 – С (О) – СН3 – oxidation of isopropylbenzene, phenol was obtained;
С6Н5 – ОН + 3HNO3 = С6Н2ОН (NO2) 3 + 3H2O – the interaction of phenol with nitric acid occurs when heated, picric acid is formed.
