Write the reaction equations: a) CaCO3- CaC2- C2H2- C2H4- C21H5Cl- cyclobutane

Write the reaction equations: a) CaCO3- CaC2- C2H2- C2H4- C21H5Cl- cyclobutane b) CH4- C2H6- C3H8- C6H14- C6H6 – C6H5NO2

Let’s execute the solution, write down the equations of the processes:

a) Calcium carbonate – calcium carbide – acetylene – ethylene – chloroethane – cyclobutane.

CaCO3 + 4C = CaC2 + 3CO – OBP, calcium carbide was formed;

CaC2 + 2H2O = Ca (OH) 2 + C2H2 – hydration, acetylene obtained;

C2H2 + H2 = C2H4 – addition, ethylene was formed;

H2C = CH2 + HCl = CH3 – CH2Cl – chloroethane is released;

CH3CH2Cl + Cl2 = C2H4Cl2 – chlorination, dichloroethane obtained;

2С2Н4Cl2 + 2Na = C4H + 2NaCl – cyclobutane is released.

b) Methane – ethane – propane – hexane – benzene – nitrobenzene

2CH4 = C2H2 + 3H2 – decomposition, acetylene is released;

С2Н2 + Н2 = Н2С = СН2 – addition, ethylene was formed;

C2H4 + H2 = C2H6 – hydrogenation, ethane obtained;

C2H6 + Cl2 = C2H5Cl + HCl – substitution, chloroethane was formed;

C2H5Cl + 2Na + CH3Cl = C3H8 + 2NaCl – propane is released during the Wurtz reaction;

C3H8 + Cl2 = C3H7Cl + HCl – chloropropane obtained;

2С3Н7Cl + 2Na = C6H14 + 2NaCl – hexane is released;

C6H14 = C6H6 + 4H2 – dehydrocyclization, benzene was formed;

C6H6 + HNO3 = C6H5NO2 + H2O – nitration, nitrobenzene was obtained.