Write the reaction equations Al2O3 – Al- AlC13- Al (OH) 3 – Al2O3

1. Electrolysis of aluminum oxide at 900 ° C.

2Аl2O3 = 4Al + 3O2.

2. The exchange reaction with the formation of aluminum chloride:

Al + FeCl3 = AlCl3.

3. Under the action of alkali on salt, a precipitate is formed in the form of hydroxide:

AlCl3 + 3NaOH = Al (OH) 3 + 3NaCl.

4. Decomposition of aluminum hydroxide at high temperature:

Al (OH) 3 = Al2O3 + 3H2O.



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