Write the reaction equations Be- BeCl2 Be (OH) 2 – BeCl2 BeO- Na2BeO2 Be (OH) 2- Na2BeO2.

I.

Interaction of metallic beryllium with chlorine at 500-700 ° C.

Be + Cl2 = BeCl2.

Reacts with alkali to form insoluble hydroxide.

BeCl2 + 2NaOH = Be (OH) 2 + 2NaCl.

Beryllium hydroxide forms salt and water with acid.

Be (OH) 2 + 2HCl = BeCl2 + 2H2O.

II.

Obtaining sodium beryllate salt.

BeO + 2NaOH = Na2BeO2 + H2O.

III.

Be (OH) 2 + 2NaOH = Na2BeO2 + 2H2O.



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