Write the reaction equations: butanol-2-butene-2- 2-bromobutane-butanol-2-butanone-2

Let’s write the equations:
Н3С – СН – ОН – СН2 – СН3 = Н3С – СН = СН – СН3 + Н2О – dehydrogenation reaction, butene-2 ​​was obtained;
Н3С – СН = СН – СН3 + HBr = H3C – CH – Br – CH2 – CH3 – addition, 2-bromobutane is released;
Н3С – СН – Br – CH2 – CH3 + KOH = H3C – CH – OH – CH2 – CH3 + KBr – exchange, butanol-2 was formed;
Н3С – СН – ОН – СН2 – СН3 + CuO = H3C – CH – (O) – C2H5 + Cu + H2O – alcohol oxidation with copper oxide, butanal-2 is formed.
The reactions show a bond between alcohols, alkenes and aldehydes. Halogenated derivatives are more active substances, they perform a binding role and are used as solvents, for example, 2-bromobutane.