Write the reaction equations: CH4 → H-C-H = O → CH3OH → CH3Cl → C2H6 → C2H5OH → CH3-C-OH = O

Let’s compose the equations:
CH4 + Cl2 = CH3Cl + HCl – substitutions, chloromethane was released;
CH3Cl + KOH = CH3OH + KCl – exchange, methanol was obtained;
CH3OH + CuO = H – C – CHO + Cu + H2O – oxidation of methanol, methanal was formed;
H – C – CHO + H2 = CH3 – OH – reduction of methanol, methyl alcohol was obtained;
CH3OH + HCl = CH3CL + H2O – exchange, chloromethane was formed;
2CH3Cl + 2Na = C2H6 + 2NaCl;
C2H6 + Cl2 = C2H5Cl + HCl – substitutions, chloroethane is released;
C2H5Cl + KOH = C2H5 – OH + KCl – exchange, ethanol was formed;
С2Н5ОН + CuO = H3C – CHO + Cu + H2O – alcohol oxidation, ethanal was obtained;
Н3С – СНО + 2Cu (OH) 2 = CH3COOH + Cu2O + H2O – oxidation of aldehyde, acetic acid was released.
The reactions confirm the possibility of synthesizing ethanol, acetic acid from methane, that is, in the process of processing natural gas.