Write the reaction equations for obtaining Fe2O3 from FeCl3. How much iron (III)

Write the reaction equations for obtaining Fe2O3 from FeCl3. How much iron (III) chloride by weight is required to obtain 16 g of iron (III) oxide?

Given:
m (Fe2O3) = 16 g

To find:
m (FeCl3) -?

Decision:
1) FeCl3 + 3NaOH => Fe (OH) 3 ↓ + 3NaCl;
2Fe (OH) 3 => Fe2O3 + 3H2O;
2) M (Fe2O3) = Mr (Fe2O3) = Ar (Fe) * N (Fe) + Ar (O) * N (O) = 56 * 2 + 16 * 3 = 160 g / mol;
3) n (Fe2O3) = m (Fe2O3) / M (Fe2O3) = 16/160 = 0.1 mol;
4) n (Fe (OH) 3) = n (Fe2O3) * 2 = 0.1 * 2 = 0.2 mol;
5) n (FeCl3) = n (Fe (OH) 3) = 0.2 mol;
6) M (FeCl3) = Mr (FeCl3) = Ar (Fe) * N (Fe) + Ar (Cl) * N (Cl) = 56 * 1 + 35.5 * 3 = 162.5 g / mol;
7) m (FeCl3) = n (FeCl3) * M (FeCl3) = 0.2 * 162.5 = 32.5 g.

Answer: The mass of FeCl3 is 32.5 g.