Write the reaction equations: methane – acetylene – acetaldehyde – acetic acid – ester – alcohol – alkene – polymer.

To solve, we write down the formulas of substances:

СН4 – С2Н2 – СН3СОН – СН3СООН – СН3СОО – С3Н7 – (-СН3 – СН – СН2-) n

2СН4 = С2Н2 + 3Н2 – methane cracking process, acetylene was obtained;
С2Н2 + Н2О = Н2С = СНОН (vinyl alcohol) = СН3 – СОН – hydration, acetaldehyde was formed;
CH3 – СОН + Ag2O = CH3COOH + 2Ag – acetic acid obtained by reaction of a silver mirror;
CH3COO – C3H7 + H2O = CH3COOH + C3H7OH – hydrolysis, propanol was formed;
С3Н7ОН = Н2О + С3Н6 – dehydration, propene was obtained;
n H3C – CH = CH2 = (-CH3 – CH – CH2-) n – polymerization, polypropylene was formed.

The solution shows the relationship between hydrocarbons, oxygenates and high molecular weight substances. The end product of the chain of transformations polypropylene is used to obtain plastic products based on it.