Write the reaction equations: starch → glucose → ethyl alcohol → acetaldehyde → acetic acid

Write the reaction equations: starch → glucose → ethyl alcohol → acetaldehyde → acetic acid → acetic acid propyl ester.

Let’s carry out the solution of the chain of transformations for organic substances:

(C6H10O5) n + nH2O = C6H12O6 (glucose) + C6H12O6 (fructose) – hydrolysis, glucose was obtained;
С6Н12О6 = 2С2Н5ОН + 2СО2 – fermentation occurs with the participation of yeast, ethyl alcohol is released;
С2Н5ОН + CuO = CH3 – COH + Cu + H2O – alcohol oxidation with copper oxide, ethanal (acetaldehyde) was obtained;
CH3 – СОН + Ag2O = CH3COOH + 2Ag – qualitative reaction to aldehyde, acetic acid and silver were formed;
CH3COOH + C3H7OH = CH3COO – C3H7 + H2O – esterification, acetic acid propyl ester is isolated;

The solution process confirms the connection between carbohydrates and oxygen-containing organic substances by the example of starch, acetic propionic ether.

CH3COO – C3H7 + H2O = CH3COOH + C3H7OH – hydrolysis, propanol was formed;
С3Н7ОН = Н2О + С3Н6 – dehydration, propene was obtained;
n H3C – CH = CH2 = (-CH3 – CH – CH2-) n – polymerization, polypropylene was formed.