X = 8 + 11 t + 6 t ^ 2 from the equation of motion find the initial speed, acceleration

| May 13, 2021 | education

X = 8 + 11 t + 6 t ^ 2 from the equation of motion find the initial speed, acceleration, the path traveled by the body in 3 s, its coordinate and average speed.

x (t) = 8 + 11 * t + 6 * t ^ 2.

t = 3 s.

V0 -?

a -?

S -?

V0 -?

Vav -?

With uniformly accelerated motion, the dependence of the coordinate on time x (t) has the form: x (t) = x0 + V0 * t + a * t ^ 2/2, where x0 is the initial coordinate, + V0 is the initial speed of motion, a is the acceleration of the body …

V0 = 11 m / s, a = 12 m / s ^ 2.

x (3s) = 8 + 11 * 3s + 6 * (3s) ^ 2 = 95.

S = x (3 s) – x0 = 95 – 8 = 87 m.

Vav = S / t.

Vav = 87 m / 3 s = 29 m / s.

V (t) = x (t) “= (8 + 11 * t + 6 * t ^ 2)” = 11 + 12 * t.

V (3 s) = 11 + 12 * 3 = 47 m / s.

Answer: a = 12 m / s ^ 2, S = 87 m, V0 = 11 m / s, Vav = 29 m / s.



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