Yeast fermentation of glucose produces ethyl alcohol. calculate the mass of glucose required to obtain a solution

| September 8, 2021 | education

Yeast fermentation of glucose produces ethyl alcohol. calculate the mass of glucose required to obtain a solution of ethyl alcohol weighing 500 kg with a mass fraction of C2H5OH 15%.

1. Alcoholic fermentation of glucose describes the reaction equation:

C6H12O6 → 2C2H5OH + 2CO2 ↑;

2. Calculate the mass of the ethanol obtained:

m (C2H5OH) = w (C2H5OH) * m (solution) = 0.15 * 500 = 75 kg;

3. Find the chemical amount of ethanol:

n (C2H5OH) = m (C2H5OH): M (C2H5OH);

M (C2H5OH) = 2 * 12 + 5 + 17 = 46 g / mol;

n (C2H5OH) = 75: 46 = 1.63 kmol;

4. Determine the amount of reacted glucose:

n (C6H12O6) = n (C2H5OH): 2 = 1.63: 2 = 0.815 kmol;

5. Let’s calculate the mass of glucose:

m (C6H12O6) = n (C6H12O6) * M (C6H12O6);

M (C6H12O6) = 6 * 12 + 12 + 6 * 16 = 180 g / mol;

m (C6H12O6) = 0.815 * 180 = 146.7 kg.

Answer: 146.7 kg.



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