You are given a circle with center O and diameter AB. Point M is taken outside the circle, so that lines MA

You are given a circle with center O and diameter AB. Point M is taken outside the circle, so that lines MA and MB intersect the circle at points C and D, respectively; AC = CD = B D. Prove that AC = OB

A drawing is needed here. There is no way to attach it, therefore, in words. By condition: AC = CD = BD Because. AC = BD, AB – diameter => CD || AB => in front of us is an isosceles trapezoid. ASO; CDO; BDO – equilateral triangles => AC = OB



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