You are given a circle with center O and diameter AB. Point M is taken outside the circle, so that lines MA and MB intersect the circle at points C and D, respectively; AC = CD = B D. Prove that AC = OB
A drawing is needed here. There is no way to attach it, therefore, in words. By condition: AC = CD = BD Because. AC = BD, AB – diameter => CD || AB => in front of us is an isosceles trapezoid. ASO; CDO; BDO – equilateral triangles => AC = OB
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.