You are given a rectangular trapezoid ABCD with an angle D at a base of 45 degrees. AB = BC = 10cm, Find AD.

Let’s draw the height of CH from the top of the obtuse angle of the trapezoid.
Since the trapezoid is rectangular, and CH is height, the quadrilateral ABCH is a rectangle.
By condition, AB = BC = 10 cm, then the ABCH quadrangle is a square with a side of 10 cm.
In a right-angled SDN triangle, one of the acute angles is 450, then the СDН triangle is rectangular and isosceles. CH = DН = 10 cm.
Determine the length of the base of the blood pressure.
AD = AН + DН = 10 + 10 = 20 cm.
Answer: The length of the blood pressure segment is 20 cm.

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