You are given an isosceles triangle ABC, in which AB = BC.

You are given an isosceles triangle ABC, in which AB = BC. The MBC angle is external and is equal to 52 degrees. Find the angles of the triangle ABC.

The angle ABC adjacent to the angle MBC, the sum of which is 180, then the angle ABC = 180 – 52 = 128.

Angle BAC = BCA = (180 – ABC) / 2 = (180 – 128) / 2 = 26.

Answer: The angles of the triangle ABC are equal to 26, 26, 128.



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