You are given nitric acid, iron oxide (lll), calcium hydroxide, calcium carbonate, zinc, copper sulfate (ll).

You are given nitric acid, iron oxide (lll), calcium hydroxide, calcium carbonate, zinc, copper sulfate (ll). With the help of these substances you will get a) iron hydroxide (lll), b) calcium nitrate, c) copper

1. Iron (III) hydroxide – an insoluble base – can be obtained by reacting its salt with alkali.

– Alkali is calcium hydroxide Ca (OH) 2.

– Salt can be obtained by the reaction of iron (III) oxide Fe2O3 with nitric acid.

Fe2O3 + 6HNO3 = 2Fe (NO3) 3 + 3H2O.

2Fe (NO3) 3 + 3Ca (OH) 2 = 2Fe (OH) 3 + 3Ca (NO3) 2.

2.Calcium nitrate is obtained by the reaction between calcium carbonate and nitric acid. Calcium nitrate, carbon dioxide and water are formed.

CaCO3 + 2HNO3 = Ca (NO3) 2 + H2O + CO2.

3. Copper can be obtained by the interaction of zinc and copper sulfate. This is a substitution reaction. Zinc is a more active metal than copper, so zinc displaces it from the CuSO4 salt.

Zn + CuSO4 = Cu + ZnSO4.



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