You have a piece of lead M1 = 120 g and T1 = 310 ° C and a piece of aluminum

| May 13, 2021 | education

You have a piece of lead M1 = 120 g and T1 = 310 ° C and a piece of aluminum M2 = 80 g and T2 = 45 ° C. The pieces were put together. Determine the steady-state temperature.

To determine the value of the steady-state temperature of two taken pieces, we will use the equality: Cc * m1 * (t1 – tp) = Ca * m2 * (tp – t2) and m1 * (t1 – tp) = m2 * (tp – t2).

Variables and constants: Сс – specific heat capacity of lead (Сс = 140 J / (kg * K)); m1 is the mass of the first piece (m1 = 120 g = 0.12 kg); t1 is the initial temperature of the first piece (t1 = 310 ° С); Ca is the specific heat capacity of aluminum (Ca = 920 J / (kg * K)); m2 is the mass of the second piece (m2 = 80 g = 0.08 kg); t2 – initial temperature of the second piece (t2 = 45 ° С).

Calculation: 140 * 0.12 * (310 – tr) = 920 * 0.08 * (tr – 45).

5208 – 16.8tr = 73.6tr – 3312.

90.4tr = 8520.

tp = 8520 / 90.4 = 94.25 ° C.

Answer: The steady-state temperature of the two pieces taken is 94.25 ° C.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.