Zinc (metal in excess) was added to a solution of hydrochloric acid with a volume of 120 ml

Zinc (metal in excess) was added to a solution of hydrochloric acid with a volume of 120 ml (mass fraction of HCl 15%, density 1.07 g / ml). Determine the volume of Hydrogen that was released as a result of the reaction.

The reaction is described by the following chemical equation:

Zn + 2HCl = ZnCl2 + H2;

Let’s calculate the chemical amount of hydrochloric acid. To do this, divide its weight by the mass of 1 mole of the substance.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 120 x 1.07 x 0.15 / 36.5 = 0.528 mol;

With this amount of acid, 0.528 / 2 = 0.264 mol of zinc will react. This will receive 0.264 mol of hydrogen and 0.264 mol of zinc chloride. Let’s determine the volume of hydrogen. For this purpose, we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V H2 = 0.264 x 22.4 = 5.9136 liters;