Zinc was burned in 5.6 liters of chlorine. The reaction product was dissolved in water, sodium hydroxide

Zinc was burned in 5.6 liters of chlorine. The reaction product was dissolved in water, sodium hydroxide was added to the resulting solution until the precipitation stopped. How much sulfuric acid is required to completely dissolve this precipitate?

1) Find the number of mol of Cl2 (Vm = 22.4 l / mol NU): n = 5.6 / 22.4 = 0.25 mol;
2) The amounts of moles of reagents and products are equal: n (Cl2) = n (Zn) = n (ZnCl2) = n (Zn (OH) 2) = n (H2SO4) = 0.25 mol;
3) Find the mass of H2SO4 (M = 98 g / mol): m = 0.25 * 98 = 24.5 g;
Answer: 24.5 g