Zinc weighing 20 g was dissolved with hydrogen chloride. Calculate the amount of the substance of the released

Zinc weighing 20 g was dissolved with hydrogen chloride. Calculate the amount of the substance of the released hydrogen and the formed zinc chloride. Specify the oxidizing agent and the reducing agent in this reaction

When dissolved in hydrochloric acid, metallic zinc is converted to a zinc chloride salt.

Zn + 2HCl = ZnCl2 + H2;

Zinc is oxidized by acid. The acid is an oxidizing agent.

In this case, hydrogen is synthesized, which can be used as a reducing agent.

Let’s determine the chemical amount of zinc. To do this, we divide its weight by the mass of 1 mole of metal.

N Zn = 20/65 = 0.31 mol;

With this amount of zinc, 0.31 x 2 = 0.62 mol of acid reacts. This will receive 0.31 mol of hydrogen and 0.31 mol of zinc chloride. Let’s calculate the volume of hydrogen. To this end, we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V H2 = 0.31 x 22.4 = 6.944 liters;