Zinc weighing 6.5 g was added to a solution of sulfuric acid taken in excess. What is the volume of released hydrogen?

The interaction of zinc with sulfate acid leads to the formation of a zinc sulfate salt and the evolution of hydrogen.
This chemical process is described by the following scheme:
Zn + H2SO4 → ZnSO4 + H2;
The coefficients in the equation are 1. Therefore, the amount of hydrogen is equal to the amount of zinc taken.
Let’s determine the chemical amount of zinc.
M Zn = 65 grams / mol;
N Zn = 6.5 / 65 = 0.1 mol;
Therefore, with this amount of zinc, it is possible to obtain 0.1 mol of hydrogen.
Find the volume of 0.1 mol of hydrogen.
Let’s multiply the amount of hydrogen by the volume of 1 mole of ideal gas:
V H2 = 22.4 x 0.1 = 2.24 liters;