Zinc weighing 6.5 g was placed in a sulfuric acid solution. Calculate the mass of the released hydrogen

| April 4, 2021 | education

Zinc weighing 6.5 g was placed in a sulfuric acid solution. Calculate the mass of the released hydrogen, the amount of the substance of the formed salt and the number of hydrogen molecules.

The equation for the reaction of zinc with sulfuric acid solution:

Zn + H2SO4 = ZnSO4 + H2

The amount of Zn substance:

v (Zn) = m (Zn) / M (Zn) = 6.5 / 65 = 0.1 (mol).

According to the reaction equation, 1 mole of ZnSO4 and 1 mole of H2 are formed per 1 mole of Zn, therefore:

v (ZnSO4) = v (H2) = v (Zn) = 0.1 (mol).

In this way:

the amount of substance of the zinc sulfate salt formed:
v (ZnSO4) = 0.1 (mol);

mass of released hydrogen:
m (H2) = v (H2) * M (H2) = 0.1 * 2 = 0.2 (g);

number of hydrogen molecules:
N (H2) = v (H2) * Na = 0.1 * 6.02 * 10 ^ 23 = 6.02 * 10 ^ 22 (molecules).



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